Base | Representation |
---|---|
bin | 1100000000111011000… |
… | …11011001110011110001 |
3 | 1110110112121212222022120 |
4 | 12000131203121303301 |
5 | 23230420021233213 |
6 | 513351000224453 |
7 | 41552611613316 |
oct | 6003543316361 |
9 | 1413477788276 |
10 | 412812680433 |
11 | 14a088aa589a |
12 | 6800a16b129 |
13 | 2cc0ac7565a |
14 | 15da1acad0d |
15 | ab11698423 |
hex | 601d8d9cf1 |
412812680433 has 16 divisors (see below), whose sum is σ = 584853736896. Its totient is φ = 258104448000.
The previous prime is 412812680429. The next prime is 412812680437. The reversal of 412812680433 is 334086218214.
It is an interprime number because it is at equal distance from previous prime (412812680429) and next prime (412812680437).
It is not a de Polignac number, because 412812680433 - 22 = 412812680429 is a prime.
It is not an unprimeable number, because it can be changed into a prime (412812680437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14286568 + ... + 14315433.
It is an arithmetic number, because the mean of its divisors is an integer number (36553358556).
Almost surely, 2412812680433 is an apocalyptic number.
It is an amenable number.
412812680433 is a deficient number, since it is larger than the sum of its proper divisors (172041056463).
412812680433 is a wasteful number, since it uses less digits than its factorization.
412812680433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28602304.
The product of its (nonzero) digits is 221184, while the sum is 42.
Adding to 412812680433 its reverse (334086218214), we get a palindrome (746898898647).
The spelling of 412812680433 in words is "four hundred twelve billion, eight hundred twelve million, six hundred eighty thousand, four hundred thirty-three".
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