Base | Representation |
---|---|
bin | 10010110001111111011101… |
… | …01000011000001101000001 |
3 | 12102020020210222000000121211 |
4 | 21120333232220120031001 |
5 | 20403130113203111340 |
6 | 223501002133450121 |
7 | 11461556220501163 |
oct | 1130775650301501 |
9 | 172206728000554 |
10 | 41300114113345 |
11 | 121833097a830a |
12 | 47702a47a0941 |
13 | 1a07779207599 |
14 | a2ad16c8a933 |
15 | 4b949db835ea |
hex | 258feea18341 |
41300114113345 has 16 divisors (see below), whose sum is σ = 49857502439808. Its totient is φ = 32841852370560.
The previous prime is 41300114113339. The next prime is 41300114113387. The reversal of 41300114113345 is 54331141100314.
It is not a de Polignac number, because 41300114113345 - 29 = 41300114112833 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83496397 + ... + 83989573.
It is an arithmetic number, because the mean of its divisors is an integer number (3116093902488).
Almost surely, 241300114113345 is an apocalyptic number.
It is an amenable number.
41300114113345 is a deficient number, since it is larger than the sum of its proper divisors (8557388326463).
41300114113345 is a wasteful number, since it uses less digits than its factorization.
41300114113345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 593640.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 41300114113345 its reverse (54331141100314), we get a palindrome (95631255213659).
The spelling of 41300114113345 in words is "forty-one trillion, three hundred billion, one hundred fourteen million, one hundred thirteen thousand, three hundred forty-five".
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