Base | Representation |
---|---|
bin | 101110111101000000100011… |
… | …0000011101011100000111001 |
3 | 2000011022220200121222021102212 |
4 | 1131322001012003223200321 |
5 | 413113134203010200040 |
6 | 4022215552244304505 |
7 | 152664433424450066 |
oct | 13572010603534071 |
9 | 2004286617867385 |
10 | 413005230553145 |
11 | 10a66159769438a |
12 | 3a3a32200a2135 |
13 | 1495b2c2a58a19 |
14 | 73db7ba1c7c6d |
15 | 32b3331aadd65 |
hex | 177a0460eb839 |
413005230553145 has 16 divisors (see below), whose sum is σ = 505259005923840. Its totient is φ = 324013259458944.
The previous prime is 413005230553129. The next prime is 413005230553159. The reversal of 413005230553145 is 541355032500314.
It is a cyclic number.
It is not a de Polignac number, because 413005230553145 - 24 = 413005230553129 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2764166180 + ... + 2764315589.
It is an arithmetic number, because the mean of its divisors is an integer number (31578687870240).
Almost surely, 2413005230553145 is an apocalyptic number.
It is an amenable number.
413005230553145 is a deficient number, since it is larger than the sum of its proper divisors (92253775370695).
413005230553145 is a wasteful number, since it uses less digits than its factorization.
413005230553145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5528482064.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 413005230553145 in words is "four hundred thirteen trillion, five billion, two hundred thirty million, five hundred fifty-three thousand, one hundred forty-five".
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