Base | Representation |
---|---|
bin | 1100000001010110001… |
… | …10111100111011011011 |
3 | 1110111010110211020121110 |
4 | 12000223012330323123 |
5 | 23231401231300011 |
6 | 513425322511403 |
7 | 41561342643255 |
oct | 6005306747333 |
9 | 1414113736543 |
10 | 413040103131 |
11 | 14a195408937 |
12 | 68072365563 |
13 | 2cc461117b6 |
14 | 15dc3daacd5 |
15 | ab2661cba6 |
hex | 602b1bcedb |
413040103131 has 16 divisors (see below), whose sum is σ = 554159208960. Its totient is φ = 273642003360.
The previous prime is 413040103127. The next prime is 413040103171. The reversal of 413040103131 is 131301040314.
It is not a de Polignac number, because 413040103131 - 22 = 413040103127 is a prime.
It is a super-2 number, since 2×4130401031312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 413040103098 and 413040103107.
It is not an unprimeable number, because it can be changed into a prime (413040103171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 948286 + ... + 1313516.
It is an arithmetic number, because the mean of its divisors is an integer number (34634950560).
Almost surely, 2413040103131 is an apocalyptic number.
413040103131 is a deficient number, since it is larger than the sum of its proper divisors (141119105829).
413040103131 is a wasteful number, since it uses less digits than its factorization.
413040103131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 367586.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 413040103131 its reverse (131301040314), we get a palindrome (544341143445).
The spelling of 413040103131 in words is "four hundred thirteen billion, forty million, one hundred three thousand, one hundred thirty-one".
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