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413040103131 = 31732179365231
BaseRepresentation
bin1100000001010110001…
…10111100111011011011
31110111010110211020121110
412000223012330323123
523231401231300011
6513425322511403
741561342643255
oct6005306747333
91414113736543
10413040103131
1114a195408937
1268072365563
132cc461117b6
1415dc3daacd5
15ab2661cba6
hex602b1bcedb

413040103131 has 16 divisors (see below), whose sum is σ = 554159208960. Its totient is φ = 273642003360.

The previous prime is 413040103127. The next prime is 413040103171. The reversal of 413040103131 is 131301040314.

It is not a de Polignac number, because 413040103131 - 22 = 413040103127 is a prime.

It is a super-2 number, since 2×4130401031312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 413040103098 and 413040103107.

It is not an unprimeable number, because it can be changed into a prime (413040103171) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 948286 + ... + 1313516.

It is an arithmetic number, because the mean of its divisors is an integer number (34634950560).

Almost surely, 2413040103131 is an apocalyptic number.

413040103131 is a deficient number, since it is larger than the sum of its proper divisors (141119105829).

413040103131 is a wasteful number, since it uses less digits than its factorization.

413040103131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 367586.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 413040103131 its reverse (131301040314), we get a palindrome (544341143445).

The spelling of 413040103131 in words is "four hundred thirteen billion, forty million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 3 173 519 2179 6537 365231 376967 1095693 1130901 63184963 189554889 795838349 2387515047 137680034377 413040103131