Base | Representation |
---|---|
bin | 1100000001010110011… |
… | …00011100110101101011 |
3 | 1110111010120112110212112 |
4 | 12000223030130311223 |
5 | 23231402113411210 |
6 | 513425413432535 |
7 | 41561361125543 |
oct | 6005314346553 |
9 | 1414116473775 |
10 | 413041544555 |
11 | 14a1962028a2 |
12 | 6807293b74b |
13 | 2cc464c7903 |
14 | 15dc4264323 |
15 | ab26804d05 |
hex | 602b31cd6b |
413041544555 has 8 divisors (see below), whose sum is σ = 504050698800. Its totient is φ = 324832672096.
The previous prime is 413041544537. The next prime is 413041544569. The reversal of 413041544555 is 555445140314.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 413041544555 - 212 = 413041540459 is a prime.
It is a super-3 number, since 3×4130415445553 (a number of 36 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 700070120 + ... + 700070709.
It is an arithmetic number, because the mean of its divisors is an integer number (63006337350).
Almost surely, 2413041544555 is an apocalyptic number.
413041544555 is a deficient number, since it is larger than the sum of its proper divisors (91009154245).
413041544555 is a wasteful number, since it uses less digits than its factorization.
413041544555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1400140893.
The product of its (nonzero) digits is 480000, while the sum is 41.
Adding to 413041544555 its reverse (555445140314), we get a palindrome (968486684869).
The spelling of 413041544555 in words is "four hundred thirteen billion, forty-one million, five hundred forty-four thousand, five hundred fifty-five".
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