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4131114269907 = 32359871221303
BaseRepresentation
bin111100000111011001100…
…110010011110011010011
3112121221010110022201111210
4330013121212103303103
51020141010223114112
612441450243511203
7604314601625562
oct74073146236323
915557113281453
104131114269907
111352aa5342219
12568779988503
1323c7407a9171
14103d387bdbd9
15726d6a72b3c
hex3c1d9993cd3

4131114269907 has 8 divisors (see below), whose sum is σ = 5747637245184. Its totient is φ = 2634333737288.

The previous prime is 4131114269881. The next prime is 4131114269921. The reversal of 4131114269907 is 7099624111314.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4131114269907 - 214 = 4131114253523 is a prime.

It is a super-2 number, since 2×41311142699072 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4131114269957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29935610583 + ... + 29935610720.

It is an arithmetic number, because the mean of its divisors is an integer number (718454655648).

Almost surely, 24131114269907 is an apocalyptic number.

4131114269907 is a deficient number, since it is larger than the sum of its proper divisors (1616522975277).

4131114269907 is a wasteful number, since it uses less digits than its factorization.

4131114269907 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59871221329.

The product of its (nonzero) digits is 326592, while the sum is 48.

The spelling of 4131114269907 in words is "four trillion, one hundred thirty-one billion, one hundred fourteen million, two hundred sixty-nine thousand, nine hundred seven".

Divisors: 1 3 23 69 59871221303 179613663909 1377038089969 4131114269907