413111444111313 has 4 divisors (see below), whose sum is σ = 550815258815088. Its totient is φ = 275407629407540.

The previous prime is 413111444111309. The next prime is 413111444111321. The reversal of 413111444111313 is 313111444111314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413111444111313 - 2² = 413111444111309 is a prime.

It is a super-2 number, since 2×413111444111313² (a number of 30 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (413111444111213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68851907351883 + ... + 68851907351888.

It is an arithmetic number, because the mean of its divisors is an integer number (137703814703772).

Almost surely, 2^{413111444111313} is an apocalyptic number.

It is an amenable number.

413111444111313 is a deficient number, since it is larger than the sum of its proper divisors (137703814703775).

413111444111313 is a wasteful number, since it uses less digits than its factorization.

413111444111313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137703814703774.

The product of its digits is 6912, while the sum is 33.

Adding to 413111444111313 its reverse (313111444111314), we get a palindrome (726222888222627).

Subtracting from 413111444111313 its reverse (313111444111314), we obtain a palindrome (99999999999999).

The spelling of 413111444111313 in words is "four hundred thirteen trillion, one hundred eleven billion, four hundred forty-four million, one hundred eleven thousand, three hundred thirteen".