Base | Representation |
---|---|
bin | 101110111101110010111111… |
… | …0011101100011111011010001 |
3 | 2000011201021021200002100210211 |
4 | 1131323211332131203323101 |
5 | 413121423023031404210 |
6 | 4022341425000324121 |
7 | 153005316623441236 |
oct | 13573457635437321 |
9 | 2004637250070724 |
10 | 413113551044305 |
11 | 10a6a3522797661 |
12 | 3a400210473641 |
13 | 149685963021c7 |
14 | 7402b342db78d |
15 | 32b60714ee38a |
hex | 177b97e763ed1 |
413113551044305 has 4 divisors (see below), whose sum is σ = 495736261253172. Its totient is φ = 330490840835440.
The previous prime is 413113551044287. The next prime is 413113551044317. The reversal of 413113551044305 is 503440155311314.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 122700726545296 + 290412824499009 = 11077036^2 + 17041503^2 .
It is not a de Polignac number, because 413113551044305 - 27 = 413113551044177 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41311355104426 + ... + 41311355104435.
It is an arithmetic number, because the mean of its divisors is an integer number (123934065313293).
Almost surely, 2413113551044305 is an apocalyptic number.
It is an amenable number.
413113551044305 is a deficient number, since it is larger than the sum of its proper divisors (82622710208867).
413113551044305 is an equidigital number, since it uses as much as digits as its factorization.
413113551044305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82622710208866.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 413113551044305 in words is "four hundred thirteen trillion, one hundred thirteen billion, five hundred fifty-one million, forty-four thousand, three hundred five".
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