413202412113331 has 4 divisors (see below), whose sum is σ = 431167734379152. Its totient is φ = 395237089847512.

The previous prime is 413202412113311. The next prime is 413202412113347. The reversal of 413202412113331 is 133311214202314.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 413202412113331 - 2¹¹ = 413202412111283 is a prime.

It is a super-2 number, since 2×413202412113331² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413202412113293 and 413202412113302.

It is not an unprimeable number, because it can be changed into a prime (413202412113311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8982661132876 + ... + 8982661132921.

It is an arithmetic number, because the mean of its divisors is an integer number (107791933594788).

Almost surely, 2^{413202412113331} is an apocalyptic number.

413202412113331 is a deficient number, since it is larger than the sum of its proper divisors (17965322265821).

413202412113331 is a wasteful number, since it uses less digits than its factorization.

413202412113331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17965322265820.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 413202412113331 its reverse (133311214202314), we get a palindrome (546513626315645).

The spelling of 413202412113331 in words is "four hundred thirteen trillion, two hundred two billion, four hundred twelve million, one hundred thirteen thousand, three hundred thirty-one".