Base | Representation |
---|---|
bin | 101110111110100000110110… |
… | …1000011101111101111110001 |
3 | 2000012001200111202122222022111 |
4 | 1131331001231003233233301 |
5 | 413130031231041441423 |
6 | 4022454554143405321 |
7 | 153015404432056123 |
oct | 13575015503575761 |
9 | 2005050452588274 |
10 | 413212043312113 |
11 | 10a7312750411a1 |
12 | 3a4173192b3841 |
13 | 14974961643106 |
14 | 74077d9005213 |
15 | 32b88d81b360d |
hex | 177d06d0efbf1 |
413212043312113 has 16 divisors (see below), whose sum is σ = 420921705229056. Its totient is φ = 405559506683520.
The previous prime is 413212043312111. The next prime is 413212043312119. The reversal of 413212043312113 is 311213340212314.
It is a cyclic number.
It is not a de Polignac number, because 413212043312113 - 21 = 413212043312111 is a prime.
It is a super-2 number, since 2×4132120433121132 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413212043312111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28142383 + ... + 40229563.
It is an arithmetic number, because the mean of its divisors is an integer number (26307606576816).
Almost surely, 2413212043312113 is an apocalyptic number.
It is an amenable number.
413212043312113 is a deficient number, since it is larger than the sum of its proper divisors (7709661916943).
413212043312113 is a wasteful number, since it uses less digits than its factorization.
413212043312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12089544.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 413212043312113 its reverse (311213340212314), we get a palindrome (724425383524427).
The spelling of 413212043312113 in words is "four hundred thirteen trillion, two hundred twelve billion, forty-three million, three hundred twelve thousand, one hundred thirteen".
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