Base | Representation |
---|---|
bin | 111100001000011101011… |
… | …010100110001111000011 |
3 | 112122001001202020221212222 |
4 | 330020131122212033003 |
5 | 1020200323011102441 |
6 | 12442155210241255 |
7 | 604355025614024 |
oct | 74103532461703 |
9 | 15561052227788 |
10 | 4132252050371 |
11 | 1353529611555 |
12 | 568a36a2622b |
13 | 23c892427343 |
14 | 104005954c4b |
15 | 727518bcd4b |
hex | 3c21d6a63c3 |
4132252050371 has 8 divisors (see below), whose sum is σ = 4136687825088. Its totient is φ = 4127817465000.
The previous prime is 4132252050331. The next prime is 4132252050397. The reversal of 4132252050371 is 1730502522314.
4132252050371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4132252050371 - 26 = 4132252050307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4132252050331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6744476 + ... + 7331606.
It is an arithmetic number, because the mean of its divisors is an integer number (517085978136).
Almost surely, 24132252050371 is an apocalyptic number.
4132252050371 is a deficient number, since it is larger than the sum of its proper divisors (4435774717).
4132252050371 is a wasteful number, since it uses less digits than its factorization.
4132252050371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 594673.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 4132252050371 its reverse (1730502522314), we get a palindrome (5862754572685).
The spelling of 4132252050371 in words is "four trillion, one hundred thirty-two billion, two hundred fifty-two million, fifty thousand, three hundred seventy-one".
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