413231344411321 has 4 divisors (see below), whose sum is σ = 413327511821812. Its totient is φ = 413135177000832.

The previous prime is 413231344411279. The next prime is 413231344411339. The reversal of 413231344411321 is 123114443132314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 126179480225296 + 287051864186025 = 11232964^2 + 16942605^2 .

It is a cyclic number.

It is not a de Polignac number, because 413231344411321 - 2²¹ = 413231342314169 is a prime.

It is a super-3 number, since 3×413231344411321³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413231344471321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48083698800 + ... + 48083707393.

It is an arithmetic number, because the mean of its divisors is an integer number (103331877955453).

Almost surely, 2^{413231344411321} is an apocalyptic number.

It is an amenable number.

413231344411321 is a deficient number, since it is larger than the sum of its proper divisors (96167410491).

413231344411321 is an equidigital number, since it uses as much as digits as its factorization.

413231344411321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96167410490.

The product of its digits is 82944, while the sum is 37.

Adding to 413231344411321 its reverse (123114443132314), we get a palindrome (536345787543635).

The spelling of 413231344411321 in words is "four hundred thirteen trillion, two hundred thirty-one billion, three hundred forty-four million, four hundred eleven thousand, three hundred twenty-one".