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413300215121 = 497478308043
BaseRepresentation
bin1100000001110101001…
…11001100110101010001
31110111210121021022011212
412000322213030311101
523232414323340441
6513511213545505
741600651602253
oct6007247146521
91414717238155
10413300215121
1114a309218922
12681254a5295
132cc87c84a11
141600a759cd3
15ab3e39ceeb
hex603a9ccd51

413300215121 has 4 divisors (see below), whose sum is σ = 413308572912. Its totient is φ = 413291857332.

The previous prime is 413300215061. The next prime is 413300215129. The reversal of 413300215121 is 121512003314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-413300215121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413300215129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4104275 + ... + 4203768.

It is an arithmetic number, because the mean of its divisors is an integer number (103327143228).

Almost surely, 2413300215121 is an apocalyptic number.

It is an amenable number.

413300215121 is a deficient number, since it is larger than the sum of its proper divisors (8357791).

413300215121 is an equidigital number, since it uses as much as digits as its factorization.

413300215121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8357790.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 413300215121 its reverse (121512003314), we get a palindrome (534812218435).

The spelling of 413300215121 in words is "four hundred thirteen billion, three hundred million, two hundred fifteen thousand, one hundred twenty-one".

Divisors: 1 49747 8308043 413300215121