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413330205534505 = 5711924179903779
BaseRepresentation
bin101110111111010111111000…
…0000100110110100100101001
32000012110222111200201210212121
41131332233300010312210221
5413134000230104101010
64023025135230111241
7153030056544303250
oct13576576004664451
92005428450653777
10413330205534505
1110a7773a0589846
123a4361b564b521
1314982b42b712bc
14740d40823d797
1532bba01b4c3da
hex177ebf0136929

413330205534505 has 16 divisors (see below), whose sum is σ = 566853385921920. Its totient is φ = 283426160343552.

The previous prime is 413330205534487. The next prime is 413330205534541. The reversal of 413330205534505 is 505435502033314.

It is a cyclic number.

It is not a de Polignac number, because 413330205534505 - 211 = 413330205532457 is a prime.

It is a super-2 number, since 2×4133302055345052 (a number of 30 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36782706 + ... + 46686484.

It is an arithmetic number, because the mean of its divisors is an integer number (35428336620120).

Almost surely, 2413330205534505 is an apocalyptic number.

It is an amenable number.

413330205534505 is a deficient number, since it is larger than the sum of its proper divisors (153523180387415).

413330205534505 is a wasteful number, since it uses less digits than its factorization.

413330205534505 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11096208.

The product of its (nonzero) digits is 1620000, while the sum is 43.

Adding to 413330205534505 its reverse (505435502033314), we get a palindrome (918765707567819).

The spelling of 413330205534505 in words is "four hundred thirteen trillion, three hundred thirty billion, two hundred five million, five hundred thirty-four thousand, five hundred five".

Divisors: 1 5 7 35 1192417 5962085 8346919 9903779 41734595 49518895 69326453 346632265 11809434443843 59047172219215 82666041106901 413330205534505