413401224433 has 4 divisors (see below), whose sum is σ = 420178293748. Its totient is φ = 406624155120.

The previous prime is 413401224427. The next prime is 413401224437. The reversal of 413401224433 is 334422104314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 190019271744 + 223381952689 = 435912^2 + 472633^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413401224433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413401224395 and 413401224404.

It is not an unprimeable number, because it can be changed into a prime (413401224437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3388534566 + ... + 3388534687.

It is an arithmetic number, because the mean of its divisors is an integer number (105044573437).

Almost surely, 2^413401224433 is an apocalyptic number.

It is an amenable number.

413401224433 is a deficient number, since it is larger than the sum of its proper divisors (6777069315).

413401224433 is an equidigital number, since it uses as much as digits as its factorization.

413401224433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6777069314.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 413401224433 its reverse (334422104314), we get a palindrome (747823328747).

The spelling of 413401224433 in words is "four hundred thirteen billion, four hundred one million, two hundred twenty-four thousand, four hundred thirty-three".