Base | Representation |
---|---|
bin | 111100001010010010111… |
… | …101010111110001010001 |
3 | 112122020011012000111000011 |
4 | 330022102331113301101 |
5 | 1020213342332203213 |
6 | 12443123014154521 |
7 | 604454633016100 |
oct | 74122275276121 |
9 | 15566135014004 |
10 | 4134224100433 |
11 | 13543507a8999 |
12 | 5692a7352a41 |
13 | 23cb17b6687b |
14 | 104151816037 |
15 | 72819aae03d |
hex | 3c292f57c51 |
4134224100433 has 12 divisors (see below), whose sum is σ = 4809528817920. Its totient is φ = 3543377975592.
The previous prime is 4134224100427. The next prime is 4134224100493. The reversal of 4134224100433 is 3340014224314.
It is not a de Polignac number, because 4134224100433 - 221 = 4134222003281 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4134224100395 and 4134224100404.
It is not an unprimeable number, because it can be changed into a prime (4134224100493) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2164441 + ... + 3599062.
It is an arithmetic number, because the mean of its divisors is an integer number (400794068160).
Almost surely, 24134224100433 is an apocalyptic number.
It is an amenable number.
4134224100433 is a deficient number, since it is larger than the sum of its proper divisors (675304717487).
4134224100433 is a wasteful number, since it uses less digits than its factorization.
4134224100433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5778156 (or 5778149 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 4134224100433 its reverse (3340014224314), we get a palindrome (7474238324747).
The spelling of 4134224100433 in words is "four trillion, one hundred thirty-four billion, two hundred twenty-four million, one hundred thousand, four hundred thirty-three".
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