Base | Representation |
---|---|
bin | 101111000000110111011111… |
… | …1101111011101111100100011 |
3 | 2000020012121112201022112221020 |
4 | 1132001232333233131330203 |
5 | 413200331303040134301 |
6 | 4023303335504100523 |
7 | 153050646340353504 |
oct | 13601567757357443 |
9 | 2006177481275836 |
10 | 413535553052451 |
11 | 10a846496937365 |
12 | 3a469b64004743 |
13 | 1499930a01657b |
14 | 7419328604bab |
15 | 32c201e7c1436 |
hex | 1781bbfbddf23 |
413535553052451 has 8 divisors (see below), whose sum is σ = 552660043060224. Its totient is φ = 275050715873160.
The previous prime is 413535553052441. The next prime is 413535553052539. The reversal of 413535553052451 is 154250355535314.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 413535553052451 - 29 = 413535553051939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 413535553052394 and 413535553052403.
It is not an unprimeable number, because it can be changed into a prime (413535553052441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 159913205611 + ... + 159913208196.
It is an arithmetic number, because the mean of its divisors is an integer number (69082505382528).
Almost surely, 2413535553052451 is an apocalyptic number.
413535553052451 is a deficient number, since it is larger than the sum of its proper divisors (139124490007773).
413535553052451 is a wasteful number, since it uses less digits than its factorization.
413535553052451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319826414241.
The product of its (nonzero) digits is 13500000, while the sum is 51.
The spelling of 413535553052451 in words is "four hundred thirteen trillion, five hundred thirty-five billion, five hundred fifty-three million, fifty-two thousand, four hundred fifty-one".
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