Base | Representation |
---|---|
bin | 10010110100101000110000… |
… | …00010110100000001101001 |
3 | 12102112221102011220010200211 |
4 | 21122110120002310001221 |
5 | 20411122233311101441 |
6 | 224010433034501121 |
7 | 11501254434252460 |
oct | 1132243002640151 |
9 | 172487364803624 |
10 | 41391003222121 |
11 | 1220890a291a43 |
12 | 4785a2b2947a1 |
13 | 1a132022abb17 |
14 | a31499cab9d7 |
15 | 4bba1d0d9a81 |
hex | 25a5180b4069 |
41391003222121 has 4 divisors (see below), whose sum is σ = 47304003682432. Its totient is φ = 35478002761812.
The previous prime is 41391003222119. The next prime is 41391003222139. The reversal of 41391003222121 is 12122230019314.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 41391003222121 - 21 = 41391003222119 is a prime.
It is not an unprimeable number, because it can be changed into a prime (41391003222521) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2956500230145 + ... + 2956500230158.
It is an arithmetic number, because the mean of its divisors is an integer number (11826000920608).
Almost surely, 241391003222121 is an apocalyptic number.
It is an amenable number.
41391003222121 is a deficient number, since it is larger than the sum of its proper divisors (5913000460311).
41391003222121 is an equidigital number, since it uses as much as digits as its factorization.
41391003222121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5913000460310.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 41391003222121 in words is "forty-one trillion, three hundred ninety-one billion, three million, two hundred twenty-two thousand, one hundred twenty-one".
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