41430103311131 has 4 divisors (see below), whose sum is σ = 41430425454600. Its totient is φ = 41429781167664.

The previous prime is 41430103311049. The next prime is 41430103311187. The reversal of 41430103311131 is 13111330103414.

41430103311131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41430103311131 - 2¹⁰ = 41430103310107 is a prime.

It is a super-3 number, since 3×41430103311131³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 41430103311131.

It is not an unprimeable number, because it can be changed into a prime (41430103311931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160878746 + ... + 161136063.

It is an arithmetic number, because the mean of its divisors is an integer number (10357606363650).

Almost surely, 2^{41430103311131} is an apocalyptic number.

41430103311131 is a deficient number, since it is larger than the sum of its proper divisors (322143469).

41430103311131 is a wasteful number, since it uses less digits than its factorization.

41430103311131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 322143468.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 41430103311131 its reverse (13111330103414), we get a palindrome (54541433414545).

The spelling of 41430103311131 in words is "forty-one trillion, four hundred thirty billion, one hundred three million, three hundred eleven thousand, one hundred thirty-one".