Base | Representation |
---|---|
bin | 1100000011101110001… |
… | …00000000111000110011 |
3 | 1110121102021122022010002 |
4 | 12001313010000320303 |
5 | 23242003441320311 |
6 | 514200003300215 |
7 | 41635045206335 |
oct | 6016704007063 |
9 | 1417367568102 |
10 | 414314401331 |
11 | 14a789750a46 |
12 | 6836907a66b |
13 | 300ba11acbc |
14 | 160a531b455 |
15 | ab9d43293b |
hex | 6077100e33 |
414314401331 has 4 divisors (see below), whose sum is σ = 414316396200. Its totient is φ = 414312406464.
The previous prime is 414314401229. The next prime is 414314401339. The reversal of 414314401331 is 133104413414.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 414314401331 - 226 = 414247292467 is a prime.
It is a super-2 number, since 2×4143144013312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 414314401294 and 414314401303.
It is not an unprimeable number, because it can be changed into a prime (414314401339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 644201 + ... + 1115178.
It is an arithmetic number, because the mean of its divisors is an integer number (103579099050).
Almost surely, 2414314401331 is an apocalyptic number.
414314401331 is a deficient number, since it is larger than the sum of its proper divisors (1994869).
414314401331 is a wasteful number, since it uses less digits than its factorization.
414314401331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1994868.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 414314401331 its reverse (133104413414), we get a palindrome (547418814745).
The spelling of 414314401331 in words is "four hundred fourteen billion, three hundred fourteen million, four hundred one thousand, three hundred thirty-one".
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