Base | Representation |
---|---|
bin | 10010110110000110101001… |
… | …01101011001001011111001 |
3 | 12102201202112100001100122022 |
4 | 21123003110231121023321 |
5 | 20412434003231004431 |
6 | 224045531122204225 |
7 | 11505020564431631 |
oct | 1133032455311371 |
9 | 172652470040568 |
10 | 41441413141241 |
11 | 12228228385323 |
12 | 47937594b3675 |
13 | 1a17ba6c53c29 |
14 | a33abcc256c1 |
15 | 4bcebd95207b |
hex | 25b0d4b592f9 |
41441413141241 has 4 divisors (see below), whose sum is σ = 41441463501312. Its totient is φ = 41441362781172.
The previous prime is 41441413141223. The next prime is 41441413141267. The reversal of 41441413141241 is 14214131414414.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41441413141241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41441413141741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23924825 + ... + 25598438.
It is an arithmetic number, because the mean of its divisors is an integer number (10360365875328).
Almost surely, 241441413141241 is an apocalyptic number.
It is an amenable number.
41441413141241 is a deficient number, since it is larger than the sum of its proper divisors (50360071).
41441413141241 is an equidigital number, since it uses as much as digits as its factorization.
41441413141241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50360070.
The product of its digits is 24576, while the sum is 35.
Adding to 41441413141241 its reverse (14214131414414), we get a palindrome (55655544555655).
The spelling of 41441413141241 in words is "forty-one trillion, four hundred forty-one billion, four hundred thirteen million, one hundred forty-one thousand, two hundred forty-one".
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