414433421331 has 4 divisors (see below), whose sum is σ = 552577895112. Its totient is φ = 276288947552.

The previous prime is 414433421291. The next prime is 414433421417. The reversal of 414433421331 is 133124334414.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 414433421331 - 2⁷ = 414433421203 is a prime.

It is a super-2 number, since 2×414433421331² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 414433421292 and 414433421301.

It is not an unprimeable number, because it can be changed into a prime (414433421431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69072236886 + ... + 69072236891.

It is an arithmetic number, because the mean of its divisors is an integer number (138144473778).

Almost surely, 2^414433421331 is an apocalyptic number.

414433421331 is a deficient number, since it is larger than the sum of its proper divisors (138144473781).

414433421331 is a wasteful number, since it uses less digits than its factorization.

414433421331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138144473780.

The product of its digits is 41472, while the sum is 33.

Adding to 414433421331 its reverse (133124334414), we get a palindrome (547557755745).

The spelling of 414433421331 in words is "four hundred fourteen billion, four hundred thirty-three million, four hundred twenty-one thousand, three hundred thirty-one".