Base | Representation |
---|---|
bin | 10010110111011110111110… |
… | …01110001000000000110011 |
3 | 12102220021221012000101111221 |
4 | 21123233133032020000303 |
5 | 20414223113014242232 |
6 | 224123412434445511 |
7 | 11511316662266215 |
oct | 1133573716100063 |
9 | 172807835011457 |
10 | 41488834134067 |
11 | 12246352291091 |
12 | 47a0992733897 |
13 | 1a1c4c35c0cb8 |
14 | a360dac1a5b5 |
15 | 4be346bb1897 |
hex | 25bbdf388033 |
41488834134067 has 4 divisors (see below), whose sum is σ = 42453690741880. Its totient is φ = 40523977526256.
The previous prime is 41488834134047. The next prime is 41488834134073. The reversal of 41488834134067 is 76043143888414.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41488834134067 - 211 = 41488834132019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41488834133996 and 41488834134014.
It is not an unprimeable number, because it can be changed into a prime (41488834134017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 482428303842 + ... + 482428303927.
It is an arithmetic number, because the mean of its divisors is an integer number (10613422685470).
Almost surely, 241488834134067 is an apocalyptic number.
41488834134067 is a deficient number, since it is larger than the sum of its proper divisors (964856607813).
41488834134067 is an equidigital number, since it uses as much as digits as its factorization.
41488834134067 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 964856607812.
The product of its (nonzero) digits is 49545216, while the sum is 61.
The spelling of 41488834134067 in words is "forty-one trillion, four hundred eighty-eight billion, eight hundred thirty-four million, one hundred thirty-four thousand, sixty-seven".
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