Base | Representation |
---|---|
bin | 111100011011110011010… |
… | …010110011110011111011 |
3 | 112201000200010012101101202 |
4 | 330123303102303303323 |
5 | 1021020341132432420 |
6 | 12455512100004415 |
7 | 606021466160522 |
oct | 74336322636373 |
9 | 15630603171352 |
10 | 4153020202235 |
11 | 13613166a9423 |
12 | 570a7209070b |
13 | 241821cb38b8 |
14 | 105015c754b9 |
15 | 73069cbe575 |
hex | 3c6f34b3cfb |
4153020202235 has 8 divisors (see below), whose sum is σ = 5053816133856. Its totient is φ = 3275621567680.
The previous prime is 4153020202231. The next prime is 4153020202237. The reversal of 4153020202235 is 5322020203514.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4153020202235 - 22 = 4153020202231 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4153020202198 and 4153020202207.
It is not an unprimeable number, because it can be changed into a prime (4153020202231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5849323874 + ... + 5849324583.
It is an arithmetic number, because the mean of its divisors is an integer number (631727016732).
Almost surely, 24153020202235 is an apocalyptic number.
4153020202235 is a deficient number, since it is larger than the sum of its proper divisors (900795931621).
4153020202235 is a wasteful number, since it uses less digits than its factorization.
4153020202235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11698648533.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 4153020202235 its reverse (5322020203514), we get a palindrome (9475040405749).
The spelling of 4153020202235 in words is "four trillion, one hundred fifty-three billion, twenty million, two hundred two thousand, two hundred thirty-five".
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