415611013041 has 99 divisors (see below), whose sum is σ = 727113205881. Its totient is φ = 236865379464.

The previous prime is 415611013039. The next prime is 415611013061. The reversal of 415611013041 is 140310116514.

The square root of 415611013041 is 644679.

It is a perfect power (a square), and thus also a powerful number.

415611013041 is a `hidden beast` number, since 4 + 1 + 5 + 611 + 0 + 1 + 3 + 0 + 41 = 666.

It is not a de Polignac number, because 415611013041 - 2¹ = 415611013039 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 415611012996 and 415611013014.

It is not an unprimeable number, because it can be changed into a prime (415611013061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 98 ways as a sum of consecutive naturals, for example, 1096598790 + ... + 1096599168.

Almost surely, 2^415611013041 is an apocalyptic number.

415611013041 is the 644679-th square number.

415611013041 is the 322340-th centered octagonal number.

It is an amenable number.

415611013041 is a deficient number, since it is larger than the sum of its proper divisors (311502192840).

415611013041 is an frugal number, since it uses more digits than its factorization.

415611013041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802 (or 389 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 415611013041 its reverse (140310116514), we get a palindrome (555921129555).

The spelling of 415611013041 in words is "four hundred fifteen billion, six hundred eleven million, thirteen thousand, forty-one".