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42000100121 = 76000014303
BaseRepresentation
bin100111000111011001…
…101010101100011001
311000102001121011001202
4213013121222230121
51142004011200441
631143343523545
73014541650330
oct470731525431
9130361534052
1042000100121
11168a2a63951
1281818b95b5
133c64563365
142066090d17
15115c3b919b
hex9c766ab19

42000100121 has 4 divisors (see below), whose sum is σ = 48000114432. Its totient is φ = 36000085812.

The previous prime is 42000100099. The next prime is 42000100147. The reversal of 42000100121 is 12100100024.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 42000100121 - 218 = 41999837977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (42000120121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3000007145 + ... + 3000007158.

It is an arithmetic number, because the mean of its divisors is an integer number (12000028608).

Almost surely, 242000100121 is an apocalyptic number.

It is an amenable number.

42000100121 is a deficient number, since it is larger than the sum of its proper divisors (6000014311).

42000100121 is an equidigital number, since it uses as much as digits as its factorization.

42000100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6000014310.

The product of its (nonzero) digits is 16, while the sum is 11.

Adding to 42000100121 its reverse (12100100024), we get a palindrome (54100200145).

The spelling of 42000100121 in words is "forty-two billion, one hundred thousand, one hundred twenty-one".

Divisors: 1 7 6000014303 42000100121