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420122013403 = 3113552323013
BaseRepresentation
bin1100001110100010011…
…10010010111011011011
31111011102000200120011111
412013101032102323123
523340402213412103
6521000144441151
742232005123061
oct6072116227333
91434360616144
10420122013403
11152199a18944
126950a0191b7
1330804396451
141649676a031
15addd21686d
hex61d1392edb

420122013403 has 4 divisors (see below), whose sum is σ = 433674336448. Its totient is φ = 406569690360.

The previous prime is 420122013371. The next prime is 420122013427. The reversal of 420122013403 is 304310221024.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 420122013403 - 25 = 420122013371 is a prime.

It is a super-2 number, since 2×4201220134032 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (420122011403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6776161476 + ... + 6776161537.

It is an arithmetic number, because the mean of its divisors is an integer number (108418584112).

Almost surely, 2420122013403 is an apocalyptic number.

420122013403 is a deficient number, since it is larger than the sum of its proper divisors (13552323045).

420122013403 is a wasteful number, since it uses less digits than its factorization.

420122013403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13552323044.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 420122013403 its reverse (304310221024), we get a palindrome (724432234427).

The spelling of 420122013403 in words is "four hundred twenty billion, one hundred twenty-two million, thirteen thousand, four hundred three".

Divisors: 1 31 13552323013 420122013403