Base | Representation |
---|---|
bin | 1100001110100010011… |
… | …10010010111011011011 |
3 | 1111011102000200120011111 |
4 | 12013101032102323123 |
5 | 23340402213412103 |
6 | 521000144441151 |
7 | 42232005123061 |
oct | 6072116227333 |
9 | 1434360616144 |
10 | 420122013403 |
11 | 152199a18944 |
12 | 6950a0191b7 |
13 | 30804396451 |
14 | 1649676a031 |
15 | addd21686d |
hex | 61d1392edb |
420122013403 has 4 divisors (see below), whose sum is σ = 433674336448. Its totient is φ = 406569690360.
The previous prime is 420122013371. The next prime is 420122013427. The reversal of 420122013403 is 304310221024.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 420122013403 - 25 = 420122013371 is a prime.
It is a super-2 number, since 2×4201220134032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (420122011403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6776161476 + ... + 6776161537.
It is an arithmetic number, because the mean of its divisors is an integer number (108418584112).
Almost surely, 2420122013403 is an apocalyptic number.
420122013403 is a deficient number, since it is larger than the sum of its proper divisors (13552323045).
420122013403 is a wasteful number, since it uses less digits than its factorization.
420122013403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13552323044.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 420122013403 its reverse (304310221024), we get a palindrome (724432234427).
The spelling of 420122013403 in words is "four hundred twenty billion, one hundred twenty-two million, thirteen thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •