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4201330155011 = 11381939105001
BaseRepresentation
bin111101001000110010110…
…010101001111000000011
3112212122100220220021001222
4331020302302221320003
51022313311004430021
612534021525545255
7612351610043063
oct75106262517003
915778326807058
104201330155011
11137a857386a30
1257a2b4b7522b
13246250880282
141074b9d513a3
15744460c96ab
hex3d232ca9e03

4201330155011 has 4 divisors (see below), whose sum is σ = 4583269260024. Its totient is φ = 3819391050000.

The previous prime is 4201330154881. The next prime is 4201330155019. The reversal of 4201330155011 is 1105510331024.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4201330155011 - 214 = 4201330138627 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4201330155019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190969552490 + ... + 190969552511.

It is an arithmetic number, because the mean of its divisors is an integer number (1145817315006).

Almost surely, 24201330155011 is an apocalyptic number.

4201330155011 is a deficient number, since it is larger than the sum of its proper divisors (381939105013).

4201330155011 is a wasteful number, since it uses less digits than its factorization.

4201330155011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 381939105012.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 4201330155011 its reverse (1105510331024), we get a palindrome (5306840486035).

The spelling of 4201330155011 in words is "four trillion, two hundred one billion, three hundred thirty million, one hundred fifty-five thousand, eleven".

Divisors: 1 11 381939105001 4201330155011