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4203133130011 = 37113598192703
BaseRepresentation
bin111101001010011110010…
…000011101010100011011
3112212211000120111212210211
4331022132100131110123
51022331004040130021
612534520453551551
7612444362061004
oct75123620352433
915784016455724
104203133130011
1113805a2092812
1257a7189455b7
1324647a27249a
1410760b5a01ab
15744ee51e3e1
hex3d29e41d51b

4203133130011 has 4 divisors (see below), whose sum is σ = 4316731322752. Its totient is φ = 4089534937272.

The previous prime is 4203133130003. The next prime is 4203133130041. The reversal of 4203133130011 is 1100313313024.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4203133130011 - 23 = 4203133130003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4203133130041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56799096315 + ... + 56799096388.

It is an arithmetic number, because the mean of its divisors is an integer number (1079182830688).

Almost surely, 24203133130011 is an apocalyptic number.

4203133130011 is a deficient number, since it is larger than the sum of its proper divisors (113598192741).

4203133130011 is a wasteful number, since it uses less digits than its factorization.

4203133130011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113598192740.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 4203133130011 its reverse (1100313313024), we get a palindrome (5303446443035).

The spelling of 4203133130011 in words is "four trillion, two hundred three billion, one hundred thirty-three million, one hundred thirty thousand, eleven".

Divisors: 1 37 113598192703 4203133130011