Search a number
-
+
42113433431123 = 79533081435837
BaseRepresentation
bin10011001001101010011000…
…01111010110110001010011
312112010000010120210012201022
421210311030033112301103
521004441302424243443
6225322351053230055
711604411065565365
oct1144651417266123
9175100116705638
1042113433431123
111246723030564a
124881a4779232b
131a66383758482
14a5843013cd35
154d070144ee68
hex264d4c3d6c53

42113433431123 has 4 divisors (see below), whose sum is σ = 42646514867040. Its totient is φ = 41580351995208.

The previous prime is 42113433431119. The next prime is 42113433431129. The reversal of 42113433431123 is 32113433431124.

42113433431123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 42113433431123 - 22 = 42113433431119 is a prime.

It is a super-2 number, since 2×421134334311232 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (42113433431129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266540717840 + ... + 266540717997.

It is an arithmetic number, because the mean of its divisors is an integer number (10661628716760).

Almost surely, 242113433431123 is an apocalyptic number.

42113433431123 is a deficient number, since it is larger than the sum of its proper divisors (533081435917).

42113433431123 is an equidigital number, since it uses as much as digits as its factorization.

42113433431123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 533081435916.

The product of its digits is 62208, while the sum is 35.

Adding to 42113433431123 its reverse (32113433431124), we get a palindrome (74226866862247).

Subtracting from 42113433431123 its reverse (32113433431124), we obtain a palindrome (9999999999999).

The spelling of 42113433431123 in words is "forty-two trillion, one hundred thirteen billion, four hundred thirty-three million, four hundred thirty-one thousand, one hundred twenty-three".

Divisors: 1 79 533081435837 42113433431123