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42131350035 = 325936252223
BaseRepresentation
bin100111001111001110…
…010110001000010011
311000202012120100002200
4213033032112020103
51142241111200120
631204353014243
73021024365205
oct471716261023
9130665510080
1042131350035
1116960059955
1281b9854383
133c857c8a28
142079698775
151168b92e90
hex9cf396213

42131350035 has 12 divisors (see below), whose sum is σ = 73027673472. Its totient is φ = 22470053328.

The previous prime is 42131350003. The next prime is 42131350097. The reversal of 42131350035 is 53005313124.

42131350035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 42131350035 - 25 = 42131350003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 42131349990 and 42131350008.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 468126067 + ... + 468126156.

It is an arithmetic number, because the mean of its divisors is an integer number (6085639456).

Almost surely, 242131350035 is an apocalyptic number.

42131350035 is a gapful number since it is divisible by the number (45) formed by its first and last digit.

42131350035 is a deficient number, since it is larger than the sum of its proper divisors (30896323437).

42131350035 is a wasteful number, since it uses less digits than its factorization.

42131350035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 936252234 (or 936252231 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

Adding to 42131350035 its reverse (53005313124), we get a palindrome (95136663159).

The spelling of 42131350035 in words is "forty-two billion, one hundred thirty-one million, three hundred fifty thousand, thirty-five".

Divisors: 1 3 5 9 15 45 936252223 2808756669 4681261115 8426270007 14043783345 42131350035