Base | Representation |
---|---|
bin | 10011001010010000101100… |
… | …10111000111001110111011 |
3 | 12112011222020012120012222122 |
4 | 21211020112113013032323 |
5 | 21010310420102101301 |
6 | 225340032215111455 |
7 | 11606036622422624 |
oct | 1145102627071673 |
9 | 175158205505878 |
10 | 42134004331451 |
11 | 12474a2701751a |
12 | 4885a2897258b |
13 | 1a682b14b0746 |
14 | a59422194a4b |
15 | 4d100738b81b |
hex | 2652165c73bb |
42134004331451 has 4 divisors (see below), whose sum is σ = 43272761205312. Its totient is φ = 40995247457592.
The previous prime is 42134004331429. The next prime is 42134004331477. The reversal of 42134004331451 is 15413340043124.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 42134004331451 - 234 = 42116824462267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (42134004331411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 569378436875 + ... + 569378436948.
It is an arithmetic number, because the mean of its divisors is an integer number (10818190301328).
Almost surely, 242134004331451 is an apocalyptic number.
42134004331451 is a deficient number, since it is larger than the sum of its proper divisors (1138756873861).
42134004331451 is a wasteful number, since it uses less digits than its factorization.
42134004331451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1138756873860.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 42134004331451 its reverse (15413340043124), we get a palindrome (57547344374575).
The spelling of 42134004331451 in words is "forty-two trillion, one hundred thirty-four billion, four million, three hundred thirty-one thousand, four hundred fifty-one".
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