Base | Representation |
---|---|
bin | 10011001111001000101101… |
… | …01011000111101001001011 |
3 | 12112202222121012020112010101 |
4 | 21213210112223013221023 |
5 | 21021031444401104210 |
6 | 225545014045430231 |
7 | 11624116635236215 |
oct | 1147442653075113 |
9 | 175688535215111 |
10 | 42301513300555 |
11 | 12529a75507273 |
12 | 48b239726b377 |
13 | 1a7b028328942 |
14 | a635930735b5 |
15 | 4d555d17da3a |
hex | 267916ac7a4b |
42301513300555 has 4 divisors (see below), whose sum is σ = 50761815960672. Its totient is φ = 33841210640440.
The previous prime is 42301513300523. The next prime is 42301513300573. The reversal of 42301513300555 is 55500331510324.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 42301513300555 - 25 = 42301513300523 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4230151330051 + ... + 4230151330060.
It is an arithmetic number, because the mean of its divisors is an integer number (12690453990168).
Almost surely, 242301513300555 is an apocalyptic number.
42301513300555 is a deficient number, since it is larger than the sum of its proper divisors (8460302660117).
42301513300555 is an equidigital number, since it uses as much as digits as its factorization.
42301513300555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8460302660116.
The product of its (nonzero) digits is 135000, while the sum is 37.
Adding to 42301513300555 its reverse (55500331510324), we get a palindrome (97801844810879).
The spelling of 42301513300555 in words is "forty-two trillion, three hundred one billion, five hundred thirteen million, three hundred thousand, five hundred fifty-five".
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