Search a number
-
+
4233225002857 = 16325970705539
BaseRepresentation
bin111101100110011111110…
…111110101111101101001
3112222200200201200102000221
4331212133313311331221
51023324121100042412
613000414451130041
7614561155552504
oct75463767657551
915880621612027
104233225002857
111392334177214
125845165a3921
13249264693ac6
14108c63cc213b
15751b1244b07
hex3d99fdf5f69

4233225002857 has 4 divisors (see below), whose sum is σ = 4259195708560. Its totient is φ = 4207254297156.

The previous prime is 4233225002849. The next prime is 4233225002863. The reversal of 4233225002857 is 7582005223324.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4233225002857 - 23 = 4233225002849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4233225002887) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12985352607 + ... + 12985352932.

It is an arithmetic number, because the mean of its divisors is an integer number (1064798927140).

Almost surely, 24233225002857 is an apocalyptic number.

It is an amenable number.

4233225002857 is a deficient number, since it is larger than the sum of its proper divisors (25970705703).

4233225002857 is a wasteful number, since it uses less digits than its factorization.

4233225002857 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25970705702.

The product of its (nonzero) digits is 806400, while the sum is 43.

The spelling of 4233225002857 in words is "four trillion, two hundred thirty-three billion, two hundred twenty-five million, two thousand, eight hundred fifty-seven".

Divisors: 1 163 25970705539 4233225002857