Base | Representation |
---|---|
bin | 111101100111010110000… |
… | …101000010001011000011 |
3 | 112222210001002221010002122 |
4 | 331213112011002023003 |
5 | 1023333001403233103 |
6 | 13001045015234455 |
7 | 614622540554663 |
oct | 75472605021303 |
9 | 15883032833078 |
10 | 4234134430403 |
11 | 1392760558629 |
12 | 58472b078a2b |
13 | 24937ac0b607 |
14 | 108d0c9b41a3 |
15 | 75215ed4b38 |
hex | 3d9d61422c3 |
4234134430403 has 4 divisors (see below), whose sum is σ = 4234140558960. Its totient is φ = 4234128301848.
The previous prime is 4234134430397. The next prime is 4234134430439. The reversal of 4234134430403 is 3040344314324.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4234134430403 - 210 = 4234134429379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4234134430103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1873775 + ... + 3461112.
It is an arithmetic number, because the mean of its divisors is an integer number (1058535139740).
Almost surely, 24234134430403 is an apocalyptic number.
4234134430403 is a deficient number, since it is larger than the sum of its proper divisors (6128557).
4234134430403 is an equidigital number, since it uses as much as digits as its factorization.
4234134430403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6128556.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 4234134430403 its reverse (3040344314324), we get a palindrome (7274478744727).
The spelling of 4234134430403 in words is "four trillion, two hundred thirty-four billion, one hundred thirty-four million, four hundred thirty thousand, four hundred three".
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