Base | Representation |
---|---|
bin | 111101110110001111101… |
… | …100010011100011000011 |
3 | 120001022100002211120221220 |
4 | 331312033230103203003 |
5 | 1024113233123141120 |
6 | 13012252341050123 |
7 | 616030160634210 |
oct | 75661754234303 |
9 | 16038302746856 |
10 | 4250133412035 |
11 | 13995205682a5 |
12 | 5878550b6943 |
13 | 24aa2a6c9154 |
14 | 1099c975cb07 |
15 | 75850878b40 |
hex | 3dd8fb138c3 |
4250133412035 has 16 divisors (see below), whose sum is σ = 7771672525056. Its totient is φ = 1942918131168.
The previous prime is 4250133411983. The next prime is 4250133412081. The reversal of 4250133412035 is 5302143310524.
It is not a de Polignac number, because 4250133412035 - 27 = 4250133411907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4250133411987 and 4250133412005.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20238730429 + ... + 20238730638.
It is an arithmetic number, because the mean of its divisors is an integer number (485729532816).
Almost surely, 24250133412035 is an apocalyptic number.
4250133412035 is a deficient number, since it is larger than the sum of its proper divisors (3521539113021).
4250133412035 is a wasteful number, since it uses less digits than its factorization.
4250133412035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40477461082.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 4250133412035 its reverse (5302143310524), we get a palindrome (9552276722559).
The spelling of 4250133412035 in words is "four trillion, two hundred fifty billion, one hundred thirty-three million, four hundred twelve thousand, thirty-five".
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