Base | Representation |
---|---|
bin | 1100011001111101001… |
… | …00001000100110000011 |
3 | 1111202020012020210011210 |
4 | 12030332210020212003 |
5 | 23440430331001313 |
6 | 523452303141203 |
7 | 42536623210164 |
oct | 6147644104603 |
9 | 1452205223153 |
10 | 426251422083 |
11 | 1548548a7353 |
12 | 6a73a8a4803 |
13 | 312702017a6 |
14 | 168b882376b |
15 | b14b3b29c3 |
hex | 633e908983 |
426251422083 has 4 divisors (see below), whose sum is σ = 568335229448. Its totient is φ = 284167614720.
The previous prime is 426251422081. The next prime is 426251422097. The reversal of 426251422083 is 380224152624.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 426251422083 - 21 = 426251422081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (426251422081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71041903678 + ... + 71041903683.
It is an arithmetic number, because the mean of its divisors is an integer number (142083807362).
Almost surely, 2426251422083 is an apocalyptic number.
426251422083 is a deficient number, since it is larger than the sum of its proper divisors (142083807365).
426251422083 is a wasteful number, since it uses less digits than its factorization.
426251422083 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142083807364.
The product of its (nonzero) digits is 184320, while the sum is 39.
The spelling of 426251422083 in words is "four hundred twenty-six billion, two hundred fifty-one million, four hundred twenty-two thousand, eighty-three".
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