Base | Representation |
---|---|
bin | 10011011010000000011010… |
… | …00011101101010100010011 |
3 | 12121002200200002221111102201 |
4 | 21231000031003231110103 |
5 | 21043141412104111130 |
6 | 230432344132424031 |
7 | 11663111430011110 |
oct | 1155001503552423 |
9 | 177080602844381 |
10 | 42675014128915 |
11 | 1266340aa38813 |
12 | 4952853a78017 |
13 | 1aa730c96b55c |
14 | a776a5b23907 |
15 | 4e011d470bca |
hex | 26d00d0ed513 |
42675014128915 has 8 divisors (see below), whose sum is σ = 58525733662560. Its totient is φ = 29262866831232.
The previous prime is 42675014128913. The next prime is 42675014128961. The reversal of 42675014128915 is 51982141057624.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 42675014128915 - 21 = 42675014128913 is a prime.
It is not an unprimeable number, because it can be changed into a prime (42675014128913) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 609643058950 + ... + 609643059019.
It is an arithmetic number, because the mean of its divisors is an integer number (7315716707820).
Almost surely, 242675014128915 is an apocalyptic number.
42675014128915 is a deficient number, since it is larger than the sum of its proper divisors (15850719533645).
42675014128915 is a wasteful number, since it uses less digits than its factorization.
42675014128915 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1219286117981.
The product of its (nonzero) digits is 4838400, while the sum is 55.
The spelling of 42675014128915 in words is "forty-two trillion, six hundred seventy-five billion, fourteen million, one hundred twenty-eight thousand, nine hundred fifteen".
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