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430002113 = 659652507
BaseRepresentation
bin11001101000010…
…100111111000001
31002222010101000012
4121220110333001
51340040031423
6110400234305
713440646322
oct3150247701
91088111005
10430002113
112007a7a52
1210000b995
136b117528
1441174449
1527b3d078
hex19a14fc1

430002113 has 4 divisors (see below), whose sum is σ = 430655280. Its totient is φ = 429348948.

The previous prime is 430002101. The next prime is 430002127. The reversal of 430002113 is 311200034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 430002113 - 28 = 430001857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (430002163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325595 + ... + 326912.

It is an arithmetic number, because the mean of its divisors is an integer number (107663820).

Almost surely, 2430002113 is an apocalyptic number.

It is an amenable number.

430002113 is a deficient number, since it is larger than the sum of its proper divisors (653167).

430002113 is an equidigital number, since it uses as much as digits as its factorization.

430002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 653166.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 430002113 is about 20736.4923022193. The cubic root of 430002113 is about 754.7854677516.

Adding to 430002113 its reverse (311200034), we get a palindrome (741202147).

It can be divided in two parts, 4300021 and 13, that added together give a palindrome (4300034).

The spelling of 430002113 in words is "four hundred thirty million, two thousand, one hundred thirteen".

Divisors: 1 659 652507 430002113