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43000231113 = 327297506193
BaseRepresentation
bin101000000011000000…
…110111010011001001
311002222202112001212100
4220003000313103021
51201031024343423
631430512104013
73051404635200
oct500300672311
9132882461770
1043000231113
1117266567094
128400835009
134093818048
14211cc34237
1511ba0c4343
hexa030374c9

43000231113 has 18 divisors (see below), whose sum is σ = 72252089754. Its totient is φ = 24571560384.

The previous prime is 43000231093. The next prime is 43000231123. The reversal of 43000231113 is 31113200034.

43000231113 is a `hidden beast` number, since 430 + 0 + 0 + 231 + 1 + 1 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 42847758009 + 152473104 = 206997^2 + 12348^2 .

It is not a de Polignac number, because 43000231113 - 28 = 43000230857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (43000231123) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 48752656 + ... + 48753537.

Almost surely, 243000231113 is an apocalyptic number.

It is an amenable number.

43000231113 is a deficient number, since it is larger than the sum of its proper divisors (29251858641).

43000231113 is a wasteful number, since it uses less digits than its factorization.

43000231113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97506213 (or 97506203 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 43000231113 its reverse (31113200034), we get a palindrome (74113431147).

The spelling of 43000231113 in words is "forty-three billion, two hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 3 7 9 21 49 63 147 441 97506193 292518579 682543351 877555737 2047630053 4777803457 6142890159 14333410371 43000231113