43003332321041 has 4 divisors (see below), whose sum is σ = 44165584545972. Its totient is φ = 41841080096112.

The previous prime is 43003332321029. The next prime is 43003332321109. The reversal of 43003332321041 is 14012323330034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 29523574273600 + 13479758047441 = 5433560^2 + 3671479^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43003332321041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43003332320995 and 43003332321013.

It is not an unprimeable number, because it can be changed into a prime (43003332321011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 581126112410 + ... + 581126112483.

It is an arithmetic number, because the mean of its divisors is an integer number (11041396136493).

Almost surely, 2^{43003332321041} is an apocalyptic number.

It is an amenable number.

43003332321041 is a deficient number, since it is larger than the sum of its proper divisors (1162252224931).

43003332321041 is a wasteful number, since it uses less digits than its factorization.

43003332321041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1162252224930.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 43003332321041 its reverse (14012323330034), we get a palindrome (57015655651075).

The spelling of 43003332321041 in words is "forty-three trillion, three billion, three hundred thirty-two million, three hundred twenty-one thousand, forty-one".