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43004113 = 60077159
BaseRepresentation
bin1010010000001…
…1000011010001
32222220211112221
42210003003101
542002112423
64133421041
71031346265
oct244030321
988824487
1043004113
1122302699
121249a781
138ba9029
1459d60a5
153b96e5d
hex29030d1

43004113 has 4 divisors (see below), whose sum is σ = 43017280. Its totient is φ = 42990948.

The previous prime is 43004069. The next prime is 43004119. The reversal of 43004113 is 31140034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 43004113 - 225 = 9449681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43004119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2428 + ... + 9586.

It is an arithmetic number, because the mean of its divisors is an integer number (10754320).

Almost surely, 243004113 is an apocalyptic number.

It is an amenable number.

43004113 is a deficient number, since it is larger than the sum of its proper divisors (13167).

43004113 is an equidigital number, since it uses as much as digits as its factorization.

43004113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13166.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 43004113 is about 6557.7521301129. The cubic root of 43004113 is about 350.3509758192.

Adding to 43004113 its reverse (31140034), we get a palindrome (74144147).

The spelling of 43004113 in words is "forty-three million, four thousand, one hundred thirteen".

Divisors: 1 6007 7159 43004113