Base | Representation |
---|---|
bin | 110000111001011010110011… |
… | …1011000010101011001111001 |
3 | 2002101212112202001201011001120 |
4 | 1201302311213120111121321 |
5 | 422333311100412433423 |
6 | 4122431024101335453 |
7 | 156410664264324012 |
oct | 14162654730253171 |
9 | 2071775661634046 |
10 | 430104054421113 |
11 | 115054117a273a6 |
12 | 402a5069707589 |
13 | 155cb83b463987 |
14 | 782d20c2d4009 |
15 | 34aced8066ee3 |
hex | 1872d67615679 |
430104054421113 has 16 divisors (see below), whose sum is σ = 578746464690240. Its totient is φ = 284098960039104.
The previous prime is 430104054421099. The next prime is 430104054421121. The reversal of 430104054421113 is 311124450401034.
It is not a de Polignac number, because 430104054421113 - 221 = 430104052323961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (430104054421123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 576631 + ... + 29334972.
It is an arithmetic number, because the mean of its divisors is an integer number (36171654043140).
Almost surely, 2430104054421113 is an apocalyptic number.
It is an amenable number.
430104054421113 is a deficient number, since it is larger than the sum of its proper divisors (148642410269127).
430104054421113 is a wasteful number, since it uses less digits than its factorization.
430104054421113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29955688.
The product of its (nonzero) digits is 23040, while the sum is 33.
The spelling of 430104054421113 in words is "four hundred thirty trillion, one hundred four billion, fifty-four million, four hundred twenty-one thousand, one hundred thirteen".
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