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430120113 = 3163787583
BaseRepresentation
bin11001101000110…
…001110010110001
31002222100100212120
4121220301302301
51340102320423
6110402544453
713441650333
oct3150616261
91088310776
10430120113
11200878675
12100068129
136b159157
14411a5453
1527b62ee3
hex19a31cb1

430120113 has 8 divisors (see below), whose sum is σ = 573850368. Its totient is φ = 286568304.

The previous prime is 430120109. The next prime is 430120121. The reversal of 430120113 is 311021034.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 430120113 - 22 = 430120109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 430120092 and 430120101.

It is not an unprimeable number, because it can be changed into a prime (430124113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38881 + ... + 48702.

It is an arithmetic number, because the mean of its divisors is an integer number (71731296).

Almost surely, 2430120113 is an apocalyptic number.

It is an amenable number.

430120113 is a deficient number, since it is larger than the sum of its proper divisors (143730255).

430120113 is a wasteful number, since it uses less digits than its factorization.

430120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89223.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 430120113 is about 20739.3373327115. The cubic root of 430120113 is about 754.8545034895.

Adding to 430120113 its reverse (311021034), we get a palindrome (741141147).

The spelling of 430120113 in words is "four hundred thirty million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 1637 4911 87583 262749 143373371 430120113