Base | Representation |
---|---|
bin | 1100100001001101001… |
… | …01010010110001001011 |
3 | 1112010021110220021010011 |
4 | 12100212211102301023 |
5 | 24021413333240021 |
6 | 525334435332351 |
7 | 43035241004410 |
oct | 6204645226113 |
9 | 1463243807104 |
10 | 430144040011 |
11 | 156472107864 |
12 | 6b4464510b7 |
13 | 317407c65ca |
14 | 16b677c4107 |
15 | b2c7ec5de1 |
hex | 6426952c4b |
430144040011 has 4 divisors (see below), whose sum is σ = 491593188592. Its totient is φ = 368694891432.
The previous prime is 430144039951. The next prime is 430144040023. The reversal of 430144040011 is 110040441034.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 430144040011 - 29 = 430144039499 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (430144040041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30724574280 + ... + 30724574293.
It is an arithmetic number, because the mean of its divisors is an integer number (122898297148).
Almost surely, 2430144040011 is an apocalyptic number.
430144040011 is a deficient number, since it is larger than the sum of its proper divisors (61449148581).
430144040011 is an equidigital number, since it uses as much as digits as its factorization.
430144040011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61449148580.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 430144040011 its reverse (110040441034), we get a palindrome (540184481045).
It can be divided in two parts, 430 and 144040011, that added together give a palindrome (144040441).
The spelling of 430144040011 in words is "four hundred thirty billion, one hundred forty-four million, forty thousand, eleven".
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