43014425113 has 4 divisors (see below), whose sum is σ = 46924827408. Its totient is φ = 39104022820.

The previous prime is 43014425107. The next prime is 43014425137. The reversal of 43014425113 is 31152441034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43014425113 - 2²¹ = 43012327961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43014425143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1955201131 + ... + 1955201152.

It is an arithmetic number, because the mean of its divisors is an integer number (11731206852).

Almost surely, 2^43014425113 is an apocalyptic number.

It is an amenable number.

43014425113 is a deficient number, since it is larger than the sum of its proper divisors (3910402295).

43014425113 is a wasteful number, since it uses less digits than its factorization.

43014425113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3910402294.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 43014425113 its reverse (31152441034), we get a palindrome (74166866147).

The spelling of 43014425113 in words is "forty-three billion, fourteen million, four hundred twenty-five thousand, one hundred thirteen".