Base | Representation |
---|---|
bin | 10011100100101000100000… |
… | …11000111010111010000011 |
3 | 12122101121010111220102210111 |
4 | 21302110100120322322003 |
5 | 21120132202403211121 |
6 | 231312211323212151 |
7 | 12031355563525450 |
oct | 1162242030727203 |
9 | 178347114812714 |
10 | 43040142241411 |
11 | 12794249271977 |
12 | 49b1574677057 |
13 | 1b0288b790523 |
14 | a8b222808827 |
15 | 4e988d6932e1 |
hex | 27251063ae83 |
43040142241411 has 4 divisors (see below), whose sum is σ = 49188733990192. Its totient is φ = 36891550492632.
The previous prime is 43040142241387. The next prime is 43040142241463. The reversal of 43040142241411 is 11414224104034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43040142241411 - 213 = 43040142233219 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43040142241471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3074295874380 + ... + 3074295874393.
It is an arithmetic number, because the mean of its divisors is an integer number (12297183497548).
Almost surely, 243040142241411 is an apocalyptic number.
43040142241411 is a deficient number, since it is larger than the sum of its proper divisors (6148591748781).
43040142241411 is an equidigital number, since it uses as much as digits as its factorization.
43040142241411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6148591748780.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 43040142241411 its reverse (11414224104034), we get a palindrome (54454366345445).
The spelling of 43040142241411 in words is "forty-three trillion, forty billion, one hundred forty-two million, two hundred forty-one thousand, four hundred eleven".
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