Base | Representation |
---|---|
bin | 110000111011110111101111… |
… | …0000110000000101011110001 |
3 | 2002110001202121010000221111010 |
4 | 1201313233132012000223301 |
5 | 422404321234202233231 |
6 | 4123245520134341133 |
7 | 156444224400600555 |
oct | 14167573606005361 |
9 | 2073052533027433 |
10 | 430441053555441 |
11 | 11517403117a965 |
12 | 4033a439aba7a9 |
13 | 15624556719576 |
14 | 784165b253865 |
15 | 34b6b5da47546 |
hex | 1877bde180af1 |
430441053555441 has 4 divisors (see below), whose sum is σ = 573921404740592. Its totient is φ = 286960702370292.
The previous prime is 430441053555413. The next prime is 430441053555493. The reversal of 430441053555441 is 144555350144034.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 430441053555441 - 231 = 430438906071793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (430441053545441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71740175592571 + ... + 71740175592576.
It is an arithmetic number, because the mean of its divisors is an integer number (143480351185148).
Almost surely, 2430441053555441 is an apocalyptic number.
It is an amenable number.
430441053555441 is a deficient number, since it is larger than the sum of its proper divisors (143480351185151).
430441053555441 is a wasteful number, since it uses less digits than its factorization.
430441053555441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143480351185150.
The product of its (nonzero) digits is 5760000, while the sum is 48.
The spelling of 430441053555441 in words is "four hundred thirty trillion, four hundred forty-one billion, fifty-three million, five hundred fifty-five thousand, four hundred forty-one".
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