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43103312121 = 314367770707
BaseRepresentation
bin101000001001001010…
…000101100011111001
311010020221111010102110
4220021022011203321
51201233421441441
631445033322533
73054066052002
oct501112054371
9133227433373
1043103312121
1117309772401
12842b266449
1340abc9a01c
14212c7c81a9
1511c4186b16
hexa092858f9

43103312121 has 4 divisors (see below), whose sum is σ = 57471082832. Its totient is φ = 28735541412.

The previous prime is 43103312111. The next prime is 43103312137. The reversal of 43103312121 is 12121330134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 43103312121 - 215 = 43103279353 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (43103312111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7183885351 + ... + 7183885356.

It is an arithmetic number, because the mean of its divisors is an integer number (14367770708).

Almost surely, 243103312121 is an apocalyptic number.

It is an amenable number.

43103312121 is a deficient number, since it is larger than the sum of its proper divisors (14367770711).

43103312121 is a wasteful number, since it uses less digits than its factorization.

43103312121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14367770710.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 43103312121 its reverse (12121330134), we get a palindrome (55224642255).

The spelling of 43103312121 in words is "forty-three billion, one hundred three million, three hundred twelve thousand, one hundred twenty-one".

Divisors: 1 3 14367770707 43103312121