Base | Representation |
---|---|
bin | 101000001001001100… |
… | …110010111001101001 |
3 | 11010020222211012100202 |
4 | 220021030302321221 |
5 | 1201234112201441 |
6 | 31445100441545 |
7 | 3054105066656 |
oct | 501114627151 |
9 | 133228735322 |
10 | 43104022121 |
11 | 1730a107886 |
12 | 842b5492b5 |
13 | 40ac188244 |
14 | 212c930c2d |
15 | 11c427719b |
hex | a09332e69 |
43104022121 has 4 divisors (see below), whose sum is σ = 45639552852. Its totient is φ = 40568491392.
The previous prime is 43104022069. The next prime is 43104022141. The reversal of 43104022121 is 12122040134.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 15428372521 + 27675649600 = 124211^2 + 166360^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43104022121 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43104022093 and 43104022102.
It is not an unprimeable number, because it can be changed into a prime (43104022141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1267765340 + ... + 1267765373.
It is an arithmetic number, because the mean of its divisors is an integer number (11409888213).
Almost surely, 243104022121 is an apocalyptic number.
It is an amenable number.
43104022121 is a deficient number, since it is larger than the sum of its proper divisors (2535530731).
43104022121 is a wasteful number, since it uses less digits than its factorization.
43104022121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2535530730.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 43104022121 its reverse (12122040134), we get a palindrome (55226062255).
The spelling of 43104022121 in words is "forty-three billion, one hundred four million, twenty-two thousand, one hundred twenty-one".
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